I fail to see why this doesn´t return true. Any ideas?
function checkNumber(num) {
if( num % num ===1 && num % 1 === num) {
return true;
};
}
checkNumber(10);
I fail to see why this doesn´t return true. Any ideas?
function checkNumber(num) {
if( num % num ===1 && num % 1 === num) {
return true;
};
}
checkNumber(10);
I’ve edited your post for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make easier to read.
See this post to find the backtick on your keyboard. The “preformatted text” tool in the editor (</>
) will also add backticks around text.
Note: Backticks are not single quotes.
It does not return true because num % num is 0 and num % 1 is also 0. Remember that % divides two numbers and returns the remainder.
I don’t think that you understand what the %
operator does.
num % num
will never equal 1
and num % 1
will only equal num
if num
is 0
.
Hahaha, I was just working out that as you said it! I feel so dumb. Thanks a lot!
Thank you, I just realised that.