Cash Register - Strange FP result

Cash Register - Strange FP result
0

#1

Hi, I’m working on the cash register challenge. Presently I am trying to ‘sort’ my change to determine how much of each denomination to give out. However in one case I am having a rather strange FP result.

My sorting looks like this:

for (let x = 0; x < cid.length; x++) {
cashInDrawer.total += cid[x][1];
switch(x) {
case 0:
cashInDrawer.pennies = cid[x][1] / .01;
break;
case 1:
cashInDrawer.nickles = cid[x][1] / .05;
break;
case 2:
cashInDrawer.dimes = cid[x][1] / .10;
break;
case 3:
cashInDrawer.quarters = cid[x][1] / .25;
break;
case 4:
cashInDrawer.dollars = cid[x][1] / 1;
break;
case 5:
cashInDrawer.fives = cid[x][1] / 5;
break;
case 6:
cashInDrawer.tens = cid[x][1] / 10;
break;
case 7:
cashInDrawer.twentys = cid[x][1] / 20;
break;
case 8:
cashInDrawer.hundreds = cid[x][1] / 100;
break;
}

Which is all fine and dandy, however for ‘nickles’ instead of getting a count of ‘41’ I get result of 40.99999999999…

Now I get that this is floating point math… But really ? I know I could ‘force’ it with ceiling or toFixed but I just wondered is this to be expected or am I missing something here? All the other denominations work fine (produce int values).

#2

You need to force it, you’re always going to get wierd results at some point because of floating point math. This is why in real-world systems you don’t ever work directly with currency using floating point: it can’t really handle it properly. You’re doing decimal maths with a binary system, and once you introduce division it will likely go tits up at some point (the result you’re getting isn’t technically wrong in base-2 either…).

The [partial] solution is normally to only ever use integers (so a penny should be 1, not 0.01), and then go from there, but it’s easier just to round in this case.