Chunky Monkey logic explanation problem

Chunky Monkey logic explanation problem
0

#1

My code is correct for all the problems, but I need help on the logic of this code why it is correct. For this code, I would slice for the first time will be slice(i=0,size), and for the next slice(i+size, size +1) which will give the newArray value when push is [[0,1,2],[3,4,5]].But, how come the array [6] still push inside the newArray? Appreciate you could help me on this logic?

Thank you.

Your code so far

function chunkArrayInGroups(arr, size) {
  // Break it up.
  var array = [];
  var newArray = [];
   
  for (i=0;i<arr.length;i+= size){
    newArray.push(arr.slice(i, size+i));
  }
  
  return newArray;
}

chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6], 3);

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#2

In the 3rd iteration of the for loop, i = 6, so when you slice(6, 9), you are capturing the 7th element through the end of the array. The slice function will only go to the end of the array even if the 2nd parameter is higher than the actual length of the array.