Tell us what’s happening:
PerryChalmers, lukaszsobek, I appreciate your help for Somme reason I am at a total loss. Perry when I entered the formula I am doing it so that the var Fahrenheit is defined. Whenever I enter the formula not as part of the definition I get null or an error saying that it was expecting a function call but got an expression. so I think its how I’m entering it.
Your code so far
function convertToF(celsius) {
var fahrenheit;
// Only change code below this line
fahrenheit = (convertToF * 9/5 + 32);
// Only change code above this line
return fahrenheit;
}
// Change the inputs below to test your code
convertToF(-10);
Your browser information:
Your Browser User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6) AppleWebKit/603.3.8 (KHTML, like Gecko) Version/10.1.2 Safari/603.3.8
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Link to the challenge:
https://www.freecodecamp.org/challenges/convert-celsius-to-fahrenheit