Convert Celsius to Fahrenheit -- None of the checks are passing

Convert Celsius to Fahrenheit -- None of the checks are passing
0

#1

Tell us what’s happening:
I’m not sure if I just misunderstood what was asked of me, or if I just made syntactical errors.
New to the site & new to webDev; sorry if the question seems dumb!

Your code so far

function convertToF(celsius) {
  var fahrenheit;
  // Only change code below this line
  var farenheit = celsius * 9.0 / 5.0 + 32.0;
  // Only change code above this line
  return fahrenheit;
}

// Change the inputs below to test your code
convertToF(0);
convertToF(-30);
convertToF(-10);
convertToF(20);
convertToF(30);

Your browser information:

Your Browser User Agent is: Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36.

Link to the challenge:


#2

You don’t want to declare the variable fahrenheit with var twice. The variable is already declared in the line above, you can just assign the formula to fahrenheit without the var

Another issue is that you have fahrenheit spelled differently in the line of code you wrote. I think that’s the main thing breaking your code.


#3

Ahh, thank you! It worked just fine after I modified the initial instatiation of var fahrenheit & that puzzled me.