# Counting Cards Can't figure it out

Counting Cards Can't figure it out
0

#1

Tell us what’s happening:
I do get only “Cards Sequence 10,J,Q,K,A should return ‘-5 Hold’” right. I was working on a couple hours already just figuring out this one thing. Can you some one explain why i get only one right? and what code should i fix in order to get passed?

``````
var count = 0;

function cc(card) {
// Only change code below this line
switch(card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count++;
break;
case 10:
case 'J':
case 'Q':
case 'K':
case 'A':
count--;
break;
}

var msg = "";
switch (count) {
case 5:
msg = "5 Bet";
case 1:
msg = "1 Bet";
case 0:
msg = "0 Hold";
case -1:
msg = "-1 Hold";
case -5:
msg = "-5 Hold";
}
return msg;
// Only change code above this line
}

// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36`.

#2

You hardcoded answers in your second switch for only 5 possible results.

What about the case that is not listed in the challenge? What if you will have two cards only provided (eg. 2 and 3) or maybe 10 cards that will count up to 10 etc?

In other words if you have first sequence:
`cards Sequence 2, 3, 4, 5, 6 should return '5 Bet'`
What result will your code display after first card (2), second (3) etc?

Change your code that it will cover all the possible ways - you can do this with switch - it will take enourmous amount of lines or you can use simple if…else…

#3

Your first switch statement looks to me to calculate count correctly.

That second switch though could get impossibly cumbersome - you would need a case statement for every possible count. That’s a lot of possibilities.

The function will then return a string with the current count and the string `Bet` if the count is positive, or `Hold` if the count is zero or negative.