# Counting Cards JS exercise -- Can you explain what's happening?

Counting Cards JS exercise -- Can you explain what's happening?
0

#1

I passed the “Counting Cards” exercise (as part of the “Basic JS” track, but I can’t say that I actually UNDERSTAND what’s happening.

So… if cc(2), then it increments by 1, since it corresponds to case 2? and so forth for cc(‘A’), it would decrement by 1 since it corresponds to case A? sorry - i’m just having trouble understanding how this works.

This is my code:

``````var count = 0;

function cc(card) {
switch(card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count++;
break;
case 10:
case 'J':
case 'Q':
case 'K':
case 'A':
count--;
}

if(count > 0) {
return count + " Bet";
} else {
return count + " Hold";
}

cc(2); cc(3); cc(7); cc('K'); cc('A');
``````

#2

NEVERMIND - I understand now how it works!

#3

Nice!

I’ve also edited your post for readability. When you enter a code block into the forum, remember to precede it with a line of three backticks and follow it with a line of three backticks to make easier to read. See this post to find the backtick on your keyboard. The “preformatted text” tool in the editor (`</>`) will also add backticks around text.

#4

I am not able to complete a task because of the space in Bet and Hold.

#5

When you concatenate count with the player's decision (Bet or Hold) you should add a space between the first double quote and the player's decision, like this: `count + " Bet"`or `count + " Hold"`. This way you get count Bet or count Hold.

As you can see in the lesson Concatenating Strings with Plus Operator:

Watch out for spaces. Concatenation does not add spaces between concatenated strings, so you’ll