# Factorialize a Number - last condition?

Factorialize a Number - last condition?
0

#1

Tell us what’s happening:

This code, as far as I can tell, factorializes any number given it, took a lot of re-reading and such. But proud of myself.
However the final challenge test is factorialize(0) returns 1, which my code doesn’t pass.
Why is that a condition? Is 0! actually 1 in math? I can’t figure out how to make that happen. Any help appreciated.

Your code so far

``````function factorialize(num) {

var array = [];
for (num; num >= 1; num--) {
array.push(num);
}
var product = array.reduce(function(previousVal, currentVal) {
return previousVal * currentVal;});

num = product;
return num;
}

factorialize(0);
``````

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Link to the challenge:

#2

Yes! `0!` equals `1`. You can add a special case in your code to check if the input is `0`.

#3

Right on. What a crazy thing for 0 to do!