freeCodeCamp Algorithm Challenge Guide: Confirm the Ending

freeCodeCamp Algorithm Challenge Guide: Confirm the Ending
0

#4

Great explanation! Thanks for breaking it down into such simple terms.


#5

I used this method to do this exercise, longer but effective.

function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
var targetLength = target.length;
var sub = str.slice(-targetLength);
if(sub === target){
return true;
}
return false;
}

confirmEnding(“open sesame”, “same”);


#6

I used this

function confirmEnding(str, target) {
  
    if (str.substr(str.length -target.length,str.length) !== target){
      return false;
    } else{
      return true;
    }
  
  return str;
}

confirmEnding("He has to give me a new name", "name");
```

#7

function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
return (str.lastIndexOf(target) === str.length - target.length) ? true : false;
}

confirmEnding(“Bastian”, “n”);


#8

Here is the way I solved this; this one took some thinking!

function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
var anyString = str.length;
var x = target.length;
var anyStringLast = str.substring(anyString - x);
return anyStringLast === target;
}


#9

Why so complicated? Any compare operator returns true or false, so we don’t need no additional true-false.
Just:
return str.substring(str.length - target.length) === target;


It is possible to write more short function
#10

Here is my solution:

function confirmEnding(str, target) {

return str.substr(str.length - target.length) === target;
}
//test
confirmEnding(“Bastian”, “n”);


#11

I solved my own using this code snippet:

function confirmEnding(str, target) {
for(var i = 0; i < str.length; i++){
if(str.substr(i-str.length) === target){
return true;
}
}
return false;
}
confirmEnding(“Bastian”, “n”);


#12

Hi - don’t think I saw this approach being used yet, also a bit longer - adds an identifier onto the end of the string, and using the target to split the string it tests whether the identifier at the end of the string was successfully split off:

function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor

var str2 = str.concat(“test”);
var split = str2.split(target);

if (split[split.length-1]===“test”) {return true;}
else {return false;}

}

confirmEnding(“Bastian”, “n”);


#13

var v = str.substr(str.length-target.length );
if (target===v){
return true;
}
else {
return false;
}
return str;
}


#14

Now, I always thinking that operator returns true or false. For the challenge, i’ll reduce my code at a “if” with return true or flase. I learn every days. :wink:


#15

I used this approach to solve the problem:

function confirmEnding(str, target) {
var arr = [];
var string = str.split("");
for(var i = 1; i <= target.length; i++){
arr.push(string.length - i);
}
arr.sort(function(a, b){return a - b;});
var arr1 = [];
for(var j = 0; j < target.length; j++){
arr1.push(string[arr[j]]);
}
if(arr1.join("") === target){
return true;
}
return false;
}

I first converted “str” into an array of letters then i used a for loop to push to the array “arr” letters from the end of the “string” array equal to the length of the “target”, then i sort the array “arr” in an ascending order then i create another array “arr1” and used another for loop to push to the array “arr1” the actual letters that “arr” array refer to it using numbers after that i compared ‘arr1.join("")’ string to the “target” string if equal in value and type then return true, if not return false.


#16

Nice, that went really smooth for a change. Almost exactly like the provided solution, just with unnecessary length-checking.

return str.substr((str.length - target.length)) === target;

I took a look at the endsWith() function and it seems to work as follows:

    if (!String.prototype.endsWith) {
      String.prototype.endsWith = function(searchString, position) {
          var subjectString = this.toString();
          if (typeof position !== 'number' || !isFinite(position) || Math.floor(position) !== position || position > subjectString.length) {
            position = subjectString.length;
          }
          position -= searchString.length;
          var lastIndex = subjectString.indexOf(searchString, position);
          return lastIndex !== -1 && lastIndex === position;
      };
    }

#17

function confirmEnding(str, target) {
var tl = target.length;
var sl = str.lenght;

var controle = str.substring(str.length-tl,str.length);
return controle==target;
}

confirmEnding(“Bastian”, “n”);


#18

function confirmEnding(str, target) {
var targetLength = target.length,
finalStr = str.substr(-targetLength),
trueOrFalse;

if(finalStr === target){
trueOrFalse = true;
} else {
trueOrFalse = false;
}

return trueOrFalse;
}

confirmEnding(“Bastian”, “n”);


#19

Basic solution
This is done without substr, simple procedural reasoning,
linear type.

function confirmEnding(str, target) {
  for (var i = 0; i < target.length; i++) {
    if (target[target.length - 1 - i] != str[str.length - 1 - i]) {
      return false;
    }
  }
  return true;
}

#20

I must have the most complicated and embarrassing approach of all:

function confirmEnding(str, target) { var array = str.split(" "); if (array.length == 1 && array[0].substring(array[0].length - 1) == target) { return true; } var lastWord = array[array.length - 1]; if (lastWord.substring(lastWord.length - target.length) == target){ return true; } return false; I got arrays on the brain.

#21

I had answer very similar to basic code, using a ternary operator, in hindsight I could’ve condensed it down to the basic solution

function confirmEnding(str, target) {
  return (str.substr(-target.length) == target)  ? true  : false;
}

confirmEnding("Bastian", "n");

#22

my code:
function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
for (var x=0 ;x < str.length; x++) {
if (str.substring(str.length-x) === target.substring(target.length-4,target.length))
return true;
}
return false;
}

confirmEnding(“Bastian”, “n”);


#23

Hello, i used slice for solve the challenge.
Here is my code
function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
return str.slice(-target.length) == target;
}
confirmEnding(“Bastian”, “n”);

As always here is my new way to do it

function confirmEnding(str, target) {
  // "Never give up and good luck will find you."
  // -- Falcor
  return str.substr(-target.length) === target;
}