Golf Code Challenge switch statement

JavaScript
1

Hi, I am trying to do the golf code challenge. When I do it with the if/else statements the code is working properly. But when I try to do it with the switch statement it is not working. I would like some help to know what is wrong with my switch statement.

Here is my if/else statement which is working perfectly

function golfScore(par, strokes) {
  // Only change code below this line

if (strokes==1) {
    return "Hole-in-one!";
  } else if (strokes<=par-2) {
   return "Eagle";
  } else if (strokes==par-1) {
    return "Birdie";
  } else if (strokes==par) {
    return "Par";
  } else if (strokes==par+1) {
    return "Bogey";
  } else if (strokes==par+2) {
    return "Double Bogey";
  } else if (strokes>=par+3) {
    return "Go Home!";
  }
 // Only change code above this line
}

// Change these values to test
golfScore(5, 4);

Here is my Switch statement which ain’t working for some values while testing.

function golfScore(par, strokes) {
  // Only change code below this line
  var result=" ";
  switch (strokes) {
    case 1:
      result="Hole-in-one!";
      break;
      
    case (strokes<=par-2):
      result="Eagle";
      break;
      
    case par-1:
      result="Birdie";
      break;
      
    case par:
      result="Par";
      break;
      
    case par+1:
      result="Bogey";
      break;
      
    case par+2:
      result="Double Bogey";
      break;
      
    case (strokes>=par+3):
      result="Go Home!";
      break;
  }
  
  return result;

  
 
  // Only change code above this line
}

// Change these values to test
golfScore(5, 4);

Your browser information:

Link to the challenge:

2

I’m not sure if this can be solved with a switch statement. switch statements are good if the variable you’re testing has a (reasonably) finite number of values it can hold. Of if you want to do something with specific values, and deal with the rest (by using default). However, switch is not very useful when dealing with ranges, especially when you have an indefinite range on both ends (like in this problem) because there’s only one default case you can use.

You can’t do case (strokes <= par - 2) because then you’ll be comparing the actual value of strokes (a number) with the value of evaluating strokes <= par - 2 (a boolean).

4

Same problem here.
Although my solution looked a bit different I couldn’t get it to work.
Did you manage to solve it eventually?