In the "Truncate a string" excersie. Why does trunSrt = str; doesn't work

In the "Truncate a string" excersie. Why does trunSrt = str; doesn't work
0

#1
function truncateString(str, num) {
 var retStr = [];
 var trunStr = [];
 var len = str.length; 
  if ( num > 3 && num < len ){
  retStr = str.slice(0, num-3);
  trunStr =  retStr .concat("..."); 
    return trunStr;
}else if ( num < 3){
  retStr = str.slice(0, num);
  trunStr =  retStr .concat("..."); 
  return trunStr;
}else{
   **//trunSrt = str;  return trunSrt;** I struggle 45 min to release I just have to return the str instead of assigning the Srt trunSrt and then returning the same.
return str;
  }
}
truncateString("A-tisket a-tasket A green and yellow basket", "A-tisket a-tasket A green and yellow basket".length);

#2

I’ve edited your post for readability. When you enter a code block into the forum, remember to precede it with a line of three backticks and follow it with a line of three backticks to make easier to read. See this post to find the backtick on your keyboard. The “preformatted text” tool in the editor (</>) will also add backticks around text.


#3

@VickkyMevawala,
I don’t really understand from what you wrote where you are having a problem.
From reading your code, ti seems that if the if case is true, you are returning a string, since you are concatenating retStr and in the other case, you are returning an empty array(since that is what you have initialized trunStr with).

I think that is the root of your problem. Make sure to read the instructions of the exercise carefully so you understand what you need to do for each case.


#4

I’ve edited your post again for readability. When you enter a code block into the forum, remember to precede it with a line of three backticks and follow it with a line of three backticks to make easier to read. See this post to find the backtick on your keyboard. The “preformatted text” tool in the editor (</>) will also add backticks around text.


#5

Thank you Ben, Will take care of the same from next time onwards.


#6

Thanks, Randell, Will take care of the same next time onwards.


#7

Hey Tomer,
I found the problem, I was assigning the value to var trunSrt but missed to put a return below it.