Intermediate Algorithm Scripting: Pig Latin; word without vowel

JavaScript
1 
function translatePigLatin(str) {
	str = str.split("")
        let vowels = 'aeiou'
	let index= str.findIndex(value => vowels.includes(value))
	if(index == 0) {
		return str.splice(index).concat(['w', 'a', 'y']).join('')
  }
	return str.splice(index).concat(str, ['a', 'y']).join('')
}

console.log(translatePigLatin("eight"))

In the instructions nothing mentions, what should the function return if a word without vowel is passed and my code pass all the test except last one…
help

2

If there is no vowel then the consonant cluster is the whole word and you just add ay at the end

Anyway, check your last splice, you have a typo there

1 Like
3

yaa I correct my last splice but what should the function should return if there is no vowels in the word e.g ‘xyz’

4

There is something you don’t understand in the first sentence of my last post?

5

Oh I got it you said this :

else if(index === -1) {
    return str.concat(['a', 'y']).join('')
  }

it returns xyzay

6

Okay - it seems to me that this should work with words without vowels:

pigLatin = str.replace(/([^aeiouy]+)(.*)/g, "$2$1ay");

Can anybody see what’s wrong?

7

y is not a vowel - can’t check the rest now, but let us know if wth that change it works

8

Thank you so much!

I would never have thought of this. In Denmark, where I reside, ‘y’ is a vowel, but I see that this is not the case for English. Thanks. :slight_smile: