Inventory Update- 88, "Bowling Ball" - 3rd test case wrong

**Tell us what’s happening:
updateInventory([[21, “Bowling Ball”], [2, “Dirty Sock”], [1, “Hair Pin”], [5, “Microphone”]], [[2, “Hair Pin”], [3, “Half-Eaten Apple”], [67, “Bowling Ball”], [7, “Toothpaste”]]) should return [[88, “Bowling Ball”], [2, “Dirty Sock”], [3, “Hair Pin”], [3, “Half-Eaten Apple”], [5, “Microphone”], [7, “Toothpaste”]].
Passed

88, “Bowling Ball” is wrong this should be 67

third test case is wrong . **

Your code so far




const convertIntoObject=arr=>{
    const inv={};
     arr.forEach((item)=>{
        inv[item[1]]=item[0]
    })

    return inv;
}

const convertToSortedArray= obj=>{
    const newArr=[];
     Object.keys(obj).sort().forEach((key)=>{
        newArr.push([obj[key], key])
    })
    return newArr;

}



function updateInventory(arr1, arr2) {
    // All inventory must be accounted for or you're fired!
    const currInv= convertIntoObject(arr1);
    const newInv=convertIntoObject(arr2);
    const updatedInv=Object.assign({}, currInv, newInv);
console.log(JSON.stringify(convertToSortedArray(updatedInv)));
return convertToSortedArray(updatedInv)

    
 
}

// Example inventory lists
var curInv = [
    [21, "Bowling Ball"],
    [2, "Dirty Sock"],
    [1, "Hair Pin"],
    [5, "Microphone"]
];

var newInv = [
    [2, "Hair Pin"],
    [3, "Half-Eaten Apple"],
    [67, "Bowling Ball"],
    [7, "Toothpaste"]
];

updateInventory(curInv, newInv);

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User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/coding-interview-prep/algorithms/inventory-update/

Ohh yes, I made a mistake. I thought you have to update the old with new values. turns out we have to add old+new if old exists. Thanks for letting me know.

Sorry for wasting time. Need to read questions more carefully before solving.