Tell us what’s happening:
Hey i just do not understand the instructions in this challenge.
Your code so far
function filteredArray(arr, elem) {
let newArr = [];
// change code below this line
for(let i =0;i<arr.length;i++){
if(arr[i].indexOf(elem) === -1){
newArr.push(arr[i]);
}
}
// change code above this line
return newArr;
}
// change code here to test different cases:
console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3));
Your browser information:
User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36
.
Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-data-structures/iterate-through-all-an-arrays-items-using-for-loops
What type will arr[i][j]
be? Will it be an array?
hi Aditya
your code works perfectly but you say you don’t understand?
Can you tell us what exactly you need clarification on?
Hey @hbar1st i actually copied the solution code.
The thing that i fo not get is arr.indexOf(elem)
No it will not be i guess
arr is an array
indexOf is a function that acts on an array
- it takes a value parameter to look for in the array and returns the index of that value if found (or -1 if not)
1 Like
I just had the issue cause of nested arrays .
Now, i have got it after some reading.
Thanks.
function filteredArray(arr, elem) {
let newArr = [];
// change code below this line
for(let i =0;i<arr.length;i++){
if(arr[i].indexOf(elem) === -1){
newArr.push(arr[i]);
}
}
// change code above this line
return newArr;
}
// change code here to test different cases:
console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3));
Why does this console log an empty array for me? Anyone?
Welp. I misunderstood that for days. Thank you. @camperextraordinaire