Pass Arguments to Avoid External Dependence in a Function

JavaScript
1

Tell us what’s happening:
PLease tell me the solution

Your code so far


// the global variable
var fixedValue = 4;

// Add your code below this line
function incrementer (one) {
  let one = fixedValue;
  
  // Add your code above this line
}

var newValue = incrementer(one + 1); // Should equal 5
console.log(fixedValue); // Should print 4

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User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/functional-programming/pass-arguments-to-avoid-external-dependence-in-a-function

2

The function should take a number, and it should return that number with one added to it. You are only supposed to change the code where it says change the code

3

function incrementer (val) {

return val+1;

Try this. Should work :slight_smile: