I have difficulty understanding how the following function works. I know that it removes an item from an array.

```
void remove(float a[], int& n, int i){
for (int j=i+1; j<n; j++)
a[j-1] = a[j];
--n;
}
```

Please help me understand the following code

0

I have difficulty understanding how the following function works. I know that it removes an item from an array.

```
void remove(float a[], int& n, int i){
for (int j=i+1; j<n; j++)
a[j-1] = a[j];
--n;
}
```

This bit of code here is shifting all elements down by 1, essentially overwriting the element at index `i`

, which is what gets “removed”.

For instance, for an array `[10,20,30,40,50]`

, if you call the function as `remove(arr, 5, 2)`

, the first iteration begins with `j=i+1`

, so `j`

is index `3`

, and the statement `a[2] = a[3]`

causes the element at index `2`

to be overwritten with the element at index `3`

, so `30`

gets replaced with `40`

. In the next (and final) iteration, `40`

gets replaced with `50`

.

This operation is commonly referred to as “shifting elements” and is common for array manipulation cases where you have to add an element/delete an element, so you have to adjust the remaining elements by “shifting them” up or down, as the case maybe, so you don’t leave “holes” in your array.