Have been working on the lesson with this ((SPOILER)ES6: Use the Rest Operator with Function Parameters) as a guide but I still don’t understand it. I don’t even see a rest operator in the instructions!

# Rest Operator with Function Parameters

Rest Operator with Function Parameters

0

The actual lesson is below. You linked to a forum post. Can you explain what part of the instructions are not clear to you?

**funkymonk**#3

I’m the same, I don’t understand what I have to do here. I’ve tried using MSDN to understand rest and spread and also reduce since there haven’t been any lessons that I can recall up to this point that help me understand reduce before being asked to work with it.

Thanks in advance for your help!

**funkymonk**#4

I got the answer but I’m still not 100% sure how it works.

```
// original code to be changed
const sum = (function() {
"use strict";
return function sum(x, y, z) {
const args = [ x, y, z ];
return args.reduce((a, b) => a + b, 0);
};
})();
console.log(sum(1, 2, 3)); // 6
// my code
const sum = (function() {
"use strict";
return function sum(...args) {
//const args = [ x, y, z ];
return args.reduce((a, b) => a + b, 0);
};
})();
console.log(sum(1, 2, 3)); // 6
```

So basically all I had to do was remove the args array and add …args into sum() ??

I’m glad I got the answer but I’m still clueless as to how I got it