I realize the hint was to go for a simple loop, but I thought there might be another way to go about it. Also, I’m having difficulty understanding the logic of a loop in this case…
I am attempting to organize the the sub-arrays in descending order so that I can call forth the first element of each sub-array and that would be the largest one. 1)Is this the best way to go about it? 2)If so, where am I going wrong?
The console says that I am not defining i, but I shouldn’t need to because i is the array of arrays…or should I? As you can see, I’m a bit confused.
Your code so far
function largestOfFour(arr) {
//create empty array
var result = [];
//organize elements into descending order
var arr1 = arr[i][j];
var arr2 = arr1.sort(function(a,b){
return (b-a);
});
//call forth first element of each subarray
result = arr1[j][0];
return result;
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
//keep tracks of arrays highest values in another array
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The idea is good, but you have to apply sort function to all sub-arrays. I don’t understand what are you trying to do with var arr1 = arr[i][j];, and like console says, the i and j variables are not declared…
But anyway, I don’t see where you want to go with that. You need a loop or something or something similar to order each element (array) of the main array.
I wrote a loop, but I’m still a bit lost on
1.Is my loop pulling out what I want from arr? (It’s not but is it close?)
and
2. Can I .push() the result from the above effort into my empty array?
Are these questions moot as I haven’t done the necessary groundwork?
If this is the case what aspects am I missing to successfully complete the groundwork?
Your code so far
function largestOfFour(arr) {
//create empty array
var result = [];
var i = "";
var j = "";
//organize elements into desending order
for(var i=0;i<4;i++) {
for(var j=0;j<4;j++){
arr.sort(function(a,b){
return(b-a);
})
}
}
//call forth first element of each subarray
result = arr[j].push();
return result;
}
I would suggest using Math.max() for finding largest number from list of numbers, a method created specifically for this and not hacking your way around
I don’t understand why this is only passing the first test. I think that I’ve gone through the process pretty meticulously. Where have I messed up?
function largestOfFour(arr) {
//create empty array
var result = [];
//declare variables
var i;
var j;
//loop through outer array to determine number of subarrays
for(i=0;i<arr.length;i++){
//store determination from outer loop
var biggest = arr[i][0];
//loop through subarrays to find biggest number
for(j=0;j<arr[i][0].length;j++){
//compare result from outer array to result from inner array
if(arr[j] > biggest){
//assign variable from outer array to result from inner array
biggest = arr[j];
}
}
//push final result onto empty array and return it
result.push(biggest);
}
return result;
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
I am trying math.max() but that doesn’t seem to be working. When I console.log() the result of it I get only the first subarray. I tried sort(), imagining that I could select the largest number through bracket notation, but sort() just copied arr as well as the sorted arr into a larger array.
I think I am right on the edge of getting it, but I am a little frustrated that I can’t figure out the correct method because I think I am skipping over an important method that would help to solve this problem easily, Please help.
Your code so far
function largestOfFour(arr) {
//create empty array
var result = [];
//declare variables
var i;
var j;
//loop through outer array to determine number of subarrays
for(i=0;i<arr.length;i++){
//store determination from outer loop
var max = arr[i];
console.log(max);
for(j=1;j>max[i].length;j++) {
if(arr[i][j]> max) {
?????
}
}
}
return result;
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
Okay. I figured it out, but I really want to know why this worked. I don’t want to give anything away, but I’ll just say that I thought that considered how many arrays there were that you would have to do two loops but I didn’t have to do this. Why didn’t I have to do two loops and then assimilate these together into a single []. Can someone explain this to me?
I posted a link to my solution below. Can someone explain to me why this worked without more?
I have to ask, did you actually come up with the solution yourself? Because it doesn’t sound like you did. Maybe don’t use a solution if you don’t understand it.
Do you know what this does? Can you explain how apply works, and why it is used? Math.max.apply(Math, arr[i])
By the way, you still have the j variable, but you are not using it.
I looked on a lot of message boards for inspiration of what other people were doing to give me a nudge in some sort of trajectory. I saw one that used Math as a parameter and as I was using arr[i] and getting nothing I plugged it in to see what would happen.
That said, I have been using j variable unsuccessfully.
I am still puzzling over how to use var j so that I can thread the values gleaned from i loop. I am puzzled by why this works and would like to know why. This doesn’t mean that I’ve given up solving the solution for myself though…
