Return the Largest number array challenge

1

Hello There,

Here is my code, I’m unsure what exactly is wrong is keeps saying the variable that I declared is undefined.

function largestOfFour(arr) {
  // You can do this!
  let largest = [];
  var highestNumber = 0;
  for (let i = 0; i < arr.length; i++) {
    for (let j = 0; j < arr[i].length; j++) {
      if (arr[i][j] > highestNumber)
        highestNumber = arr[i][j];
}
largest.push(highestNumber);
  }
  return largest;
}

console.log(largest);
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2 
console.log(largest);

That variable largest doesn’t exist at that point. It exists inside largestOfFour, it’s “scope”.

You need access it through your function, like this:

function largestOfFour(arr) {
  // You can do this!
  let largest = [];
  var highestNumber = 0;
  for (let i = 0; i < arr.length; i++) {
    for (let j = 0; j < arr[i].length; j++) {
      if (arr[i][j] > highestNumber)
        highestNumber = arr[i][j];
}
largest.push(highestNumber);
  }
  return largest;
}

console.log(largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]));
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