# Slice and Splice alternate solution?

Slice and Splice alternate solution?
0
#1

Tell us what’s happening:
I could be mistaken, since I’m relatively new at this, but while the solution uses a for loop, wouldn’t this be essentialy the same? I get the “All elements from the first array should be added to the second array in their original order.” error but I don’t see how this would mess up the order. Thank you for any help.
Your code so far

function frankenSplice(arr1, arr2, n) {
// It's alive. It's alive!
let copy = arr1.slice();
let newArr = arr2.slice();
newArr.splice(n, 0, copy);
return newArr;
}

console.log(frankenSplice([1, 2, 3], [4, 5], 1));
console.log(frankenSplice([1, 2], ["a", "b"], 1));
console.log(frankenSplice(["claw", "tentacle"], ["head", "shoulders", "knees", "toes"], 2));

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#2

So try adding a console.log() just before you return. I can see what’s going wrong, you’re inserting an array at the given position. Not inserting the array elements, but the entire array as that given element.

The line I added (just prior to your return statement) that cleared this up for me looks like:

console.log(arr1, arr2, newArr);

Are you familiar with the spread operator yet?

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#3

Right… Yeah, I see what you mean. I was looking at the console and seeing the expected output but didn’t realize it was inserting an array instead of the values. Now I just feel dumb.
Thank you for the answer!

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#4

Don’t feel dumb, we learn best by breaking things.

Seriously, when you explore other ways of doing things, finding out why something works or doesn’t, that’s when you learn. Not saying the lessons and challenges are pointless, they aren’t – so long as they get you exploring and challenging your (and their) limits.

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#5

Yeah, I wasn’t putting myself down or anything, this happen to me all the time. An obvious error will be staring me right in the eye and I won’t see it, but in retrospective it’s really simple and silly. But I’ll get through this and learn. Thanks again

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