Understanding Order

JavaScript
1

If I have an array. Will doing this for-loop get my end result which is ‘yo’?

var list = ['words', 'three', 'yo', 'up']

function tieBreaker(array) {
  var first = '';
  for(var i = 0; i < list.length; i++) {
    if(list[i].length <= first.length) {
      first = list[i];
    } else if(list[i].length === list[i].length) {
     first = list[0];
    }
  return first;
  }
}
2

Response to your question, I did try to execute the code and when it comes to ‘yo’ and ‘up’, the code returns back ‘up’ when in fact that ‘yo’ should be the correct response.

3

Your code is a mess.

  1. You use return in for loop - which means it will stop during first iteration.
  2. You use array parameter in your function, but never use it within function.
  3. Code list[i].length === list[i].length will always return true.

Try to rewrite your function in that way:

  1. It compares every item in an array with variable first.
  2. First should have assigned initial value already - try first index.
  3. When item from current iteration is smaller that first, reassign current item to first else do nothing.
  4. After for…loop return first.
1 Like
4

Thank @wawraf for setting me straight. I really appreciate it