Use typeof to Check the Type of a Variable[Solved]

Tell us what’s happening:
I don’t understand whare is the wrong>

Your code so far


let seven = 7;
let three = "3";
console.log(seven + three);
// Add your code below this line
console.log(typeof(""));

console.log(typeof(0));

console.log(typeof([]));

console.log(typeof({}));

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/debugging/use-typeof-to-check-the-type-of-a-variable

In order to complete the challenge you don’t just want to copy the examples the lesson gives you. It says to create a typeof each for seven and three, so two total.

So the first will be: console.log(typeof seven);
and the second will be: console.log(typeof three);

The lesson could’ve been tricky if you thought to use double quotes to make it a string since it was a word instead of a number