Where is a mistake?

JavaScript
1

It is my code. It doesn’t work

for (let i = 0; i < contacts.length; i++){
  if (name == contacts[i].firstName){
    if (contacts[i].hasOwnProperty(prop)){
      console.log(contacts[i][prop]);
      return contacts[i][prop];
    } else {
      return "No such property";
    }
  } else {
    return "No such contact";
  }
}

It is basic code solution. It works

for (var x = 0; x < contacts.length; x++){
    if (contacts[x].firstName === name) {
        if (contacts[x].hasOwnProperty(prop)) {
            return contacts[x][prop];
        } else {
            return "No such property";
        }
    }
}
return "No such contact";

Exercise link
Help guys!
2

console.log(name == contacts[i].firstName);

before if (name == contacts[i].firstName){

3

That is not the mistake

4

No, is not a mistake but you can see that your loop is not going further and your function returns to early.
Never gets console.log(name == contacts[i].firstName) is true (for the failure case).
(console.log(name == contacts[i].firstName) should return true eventually because the name parameter is indeed the same as contact[3].firstName but your loop never gets there, for lookUpProfile(“Kristian”, “lastName”)) example)

Basically you want to review the if else logic from your code.

Does that help?

Quick fix:

function lookUpProfile(name, prop){
// Only change code below this line
for (let i = 0; i < contacts.length; i++){
  if (name == contacts[i].firstName){
    if (contacts[i].hasOwnProperty(prop)){
      console.log(contacts[i][prop]);
      return contacts[i][prop];
    } else {
      return "No such property";
    }
  }// else {
   // return "No such contact";
   //}
}
return "No such contact";
// Only change code above this line
}

The solution is to remove the return ‘No such contact’ from the loop body so you prevent the iteration being stopped too early.