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1/3(6x-3)=-x+10+3x

We move all terms to the left:

1/3(6x-3)-(-x+10+3x)=0

Domain of the equation: 3(6x-3)!=0We add all the numbers together, and all the variables

x∈R

1/3(6x-3)-(2x+10)=0

We get rid of parentheses

1/3(6x-3)-2x-10=0

We multiply all the terms by the denominator

-2x*3(6x-3)-10*3(6x-3)+1=0

Wy multiply elements

-6x^2(6-30x(6+1=0

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