## Quick Solution

``````function randomRange(myMin, myMax) {
return Math.floor(Math.random() * (myMax - myMin + 1) + myMin);
}
``````

## Code Explanation

• `Math.random()` generates our random number between 0 and ≈ 0.9.
• Before multiplying it, it resolves the part between parenthesis `(myMax - myMin + 1)` because of the grouping operator `(   )`.
• The result of that multiplication is followed by adding `myMin` and then "rounded" to the largest integer less than or equal to it (eg: 9.9 would result in 9)

If the values were `myMin = 1, myMax= 10`, one result could be the following:

1. `Math.random() = 0.8244326990411024`
2. `(myMax - myMin + 1) = 10 - 1 + 1 -> 10`
3. `a * b =  8.244326990411024`
4. `c + myMin = 9.244326990411024`
5. `Math.floor(9.244326990411024) = 9`

`randomRange` should use both `myMax` and `myMin`, and return a random number in your range.

You cannot pass the test if you are only re-using the function `ourRandomRange` inside your `randomRange` formula. You need to write your own formula that uses the variables `myMax` and `myMin`. It will do the same job as using `ourRandomRange`, but ensures that you have understood the principles of the `Math.floor()` and `Math.random()` functions.