Quick Solution

function randomRange(myMin, myMax) {
  return Math.floor(Math.random() * (myMax - myMin + 1) + myMin);
}

Code Explanation

  • Math.random() generates our random number between 0 and ≈ 0.9.
  • Before multiplying it, it resolves the part between parenthesis (myMax - myMin + 1) because of the grouping operator (   ).
  • The result of that multiplication is followed by adding myMin and then "rounded" to the largest integer less than or equal to it (eg: 9.9 would result in 9)

If the values were myMin = 1, myMax= 10, one result could be the following:

  1. Math.random() = 0.8244326990411024
  2. (myMax - myMin + 1) = 10 - 1 + 1 -> 10
  3. a * b =  8.244326990411024
  4. c + myMin = 9.244326990411024
  5. Math.floor(9.244326990411024) = 9

randomRange should use both myMax and myMin, and return a random number in your range.

You cannot pass the test if you are only re-using the function ourRandomRange inside your randomRange formula. You need to write your own formula that uses the variables myMax and myMin. It will do the same job as using ourRandomRange, but ensures that you have understood the principles of the Math.floor() and Math.random() functions.